Abstract:
For a finite group $G$, we denote by $N(G)$ the set of its conjugacy class sizes. Recently, the following question was posed: given any $n\in\mathbb{N}$ and an arbitrary non-Abelian finite simple group $S$, is it true that $G\simeq S^n$ if $G$ is a group with trivial center and $N(G)=N(S^n)$? The answer to this question is known for all simple groups $S$ with $n=1$, and also for $S\in\{A_5,A_6\}$, where $A_k$ denotes the alternating group of degree $k$, with $n=2$. It is proved that the group $A_5\times A_5\times A_5$ is uniquely defined by the set $N(A_5\times A_5\times A_5)$ in the class of finite groups with trivial center.